Python Reading Wiegand Dropping Zeros

Here's the code snippet from my RFID wiegand reader on my Raspberry Pi I use already. def main(): set_procname('Wiegand Reader') global bits global timeout GPIO.add

Solution 1:

Python will remove the front few bits if they are zero, this also applies to integers. For example

>>>a = 0003>>>a
3
>>>b = 0b0011>>>bin(b)
0b11

From what I see, all RFID's will have 10 numbers. You can make a simple program to add those numbers in and store the value as a string:

defrfid_formatter(value):
    str_value = str(value)
    for s inrange(10 - len(str_value)):
        str_value = "0" + str_value
    return str_value

Your test cases:

print rfid_formatter(120368)
print"0000120368"print rfid_formatter(4876298)
print"0004876298"

Solution 2:

As mentioned already, leading zeros are removed in binary sequences and also when you explicitly convert a string to decimal using int().

What hasn't been mentioned already is that, in Python 2.x, integers with leading zeros are treated as octal values.

>>>a = 0003>>>a
3
>>>a = 000127>>>a
87

Since this was causing confusion, the implicit octal conversion was removed in Python 3 and any number of leading zeros in numerical values will raise a SyntaxError.

>>>a = 000127
  File "<stdin>", line 1
    a = 000127
             ^
SyntaxError: invalid token
>>>

You can read the rationale behind these decisions in PEP 3127.

Anyway, I mention all of this simply to arrive at an assumption: you're probably not working with octal representations. Instead, I think you're converting result to a string in checkAccess so you can do a string comparison. If this assumption is correct, you can simply use the string method zfill (zero fill):

>>>str(119994).zfill(10)
'0000119994'
>>>>>>str(4876298).zfill(10)
'0004876298'
>>>