How Can I Print All Values That Are True According To The Statement Provided

so I programmed my code in a way that whenever an input number is given, the output will always only display '1' or '4' after squaring each digit of the number AND adding the value

Solution 1:

Explanation of infinite loop for 0:

If we start loop from 0 it appears a infinite loop state because it never match x not in ['1', '4'] this condition. To overcome this we can ignore 0 or put a condition to check if number is 0 or not.

Try this:

defGetX(number):
    sum_of_digits = 0
    x = ''while x notin ['1', '4']:
        for digit instr(number):
           sum_of_digits += (int(digit)**2)
        x = str(sum_of_digits)
        number = sum_of_digits
        sum_of_digits = 0return x


defIsHappy(x):
    if x == '1':
        returnTrueelse:
        returnFalsefor x inrange(1, 101):
    if IsHappy((GetX(x))):
        print(x)

# or store happy number in a list
res = [x for x inrange(1, 101) if IsHappy((GetX(x)))]
print(res)

Output:

171013192328313244496870798286919497100
[1, 7, 10, 13, 19, 23, 28, 31, 32, 44, 49, 68, 70, 79, 82, 86, 91, 94, 97, 100]

Solution 2:

Put the code that calculates the sum of digits in a function. You can then call the function in a loop.

defget_sum_of_digits(number):
    x = ''while x notin ['1', '4']:
        sum_of_digits = sum(int(digit)**2for digit instr(number))
        x = str(sum_of_digits)
    return x

defIsHappy(x):
    if x == '1':
        return'True'else:
        return'False'for i inrange(1, 100):
    if IsHappy(get_sum_of_digits(i)) == 'True':
        print(i)