Python (2.x) List / Sublist Selection -1 Weirdness
Solution 1:
In list[first:last]
, last
is not included.
The 10th element is ls[9]
, in ls[0:10]
there isn't ls[10]
.
Solution 2:
If you want to get a sub list including the last element, you leave blank after colon:
>>>ll=range(10)>>>ll
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>>ll[5:]
[5, 6, 7, 8, 9]
>>>ll[:]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Solution 3:
I get consistent behaviour for both instances:
>>> ls[0:10][0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> ls[10:-1][10, 11, 12, 13, 14, 15, 16, 17, 18]
Note, though, that tenth element of the list is at index 9, since the list is 0-indexed. That might be where your hang-up is.
In other words, [0:10]
doesn't go from index 0-10, it effectively goes from 0 to the tenth element (which gets you indexes 0-9, since the 10 is not inclusive at the end of the slice).
Solution 4:
when slicing an array;
ls[y:x]
takes the slice from element y upto and but not including x. when you use the negative indexing it is equivalent to using
ls[y:-1] == ls[y:len(ls)-1]
so it so the slice would be upto the last element, but it wouldn't include it (as per the slice)
Solution 5:
-1 isn't special in the sense that the sequence is read backwards, it rather wraps around the ends. Such that minus one means zero minus one, exclusive (and, for a positive step value, the sequence is read "from left to right".
so for i = [1, 2, 3, 4]
, i[2:-1]
means from item two to the beginning minus one (or, 'around to the end'), which results in [3]
.
The -1th element, or element 0 backwards 1 is the last 4
, but since it's exclusive, we get 3.
I hope this is somewhat understandable.
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