Converting Individual Digits To String
I think i'm very close but i cant seem to fix my issues. I need a function that takes a 10-digit input from user (me) and sets each letter to is numeric value. Example: user inputs
Solution 1:
phone_number = '941-019-aBcD'# A map of what letters to convert to what digits.# I've added q and wxy & z.
digit_map = {
'abc': 2,
'def': 3,
'ghi': 4,
'jkl': 5,
'mno': 6,
'pqrs': 7,
'tuv': 8,
'wxyz': 9
}
# Break this out into one letter per entry in the dictionary# to make the actual work of looking it up much simpler.# This is a good example of taking the data a person might# have to deal with and making it easier for a machine to# work with it.
real_map = {}
for letters, number in digit_map.iteritems():
for letter in letters:
real_map[letter] = number
# Empty new variable.
numeric_phone = ''# For each character try to 'get' the number from the 'real_map'# and if that key doesn't exist, just use the value in the# original string. This lets existing numbers and other# characters like - and () pass though without any special# handling.# Note the call to `lower` that converts all our letters to# lowercase. This will have no effect on the existing numbers# or other speacial symbols.for ch in phone_number.lower():
numeric_phone += str(real_map.get(ch, ch))
print(numeric_phone)
Solution 2:
defmain(phone_number):
digits = ["2", "3", "4", "5", "6", "7", "8", "9"]
numeric_phone=" "for ch in phone_number:
if ch.isalpha():
iford(ch) >= 97:
ch = +2 (ord(ch)-97)/3else:
ch = +2 (ord(ch)-65)/3
numeric_phone= numeric_phone+ch
print (numeric_phone)
Use ord() to convert chars to their ASCII values and then get the right number.
Solution 3:
You can create a formula to ascertain the correct number to add depending on the letter:
math.ceil((index(char)+1)/3)
Use a list and depending on which character it is, append a number to the list. At the end, return the list, but join
ed so that it is a string:
def numerify(inp):
from math import ceil as _ceil
fromstring import lowercase as _lowercase
chars = []
forcharin inp:
ifchar.isalpha():
num = _ceil((_lowercase.index(char)+1)/float(3))
chars.append(str(int(num+1)))
else:
chars.append(char)
return''.join(chars)
>>>from numerify import numerify>>>numerify('1')
'1'
>>>numerify('941-019-abcd')
'941-019-2223'
>>>
Solution 4:
I think it's easiest to pre-calculate the number character for each letter.
# len(keys) == 26 so that the index of a letter# maps to its phone keykeys = ['2']*3 + ['3']*3 \
+ ['4']*3 + ['5']*3 + ['6']*3 \
+ ['7']*4 + ['8']*3 + ['9']*4
def letter_to_key(x):
if x.isalpha():
# calculate the 'index' of a letter.# a=0, b=1, ..., z=25index = ord(x.lower()) - ord('a')
returnkeys[index]
# If it's not a letter don't change it.returnx
def translate_digits(phone_num):
return''.join(map(letter_to_key, phone_num))
print(translate_digits('941-019-abcd'))
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