Cannot Associate Image To Tkinter Label

I am trying to display an image to a tkinter GUI using tkinter.Label() widget. The procedure seems simple and straightforward, but this code doesn't work! code: import Tkinter as t

Solution 1:

This problem happens when we attempt to run the above code in Ipython. And it can be solved by changing the line

root = tk.Tk() to

root = tk.Toplevel()

Solution 2:

You need to create the root widget before you call any other tkinter functions. Move the creation of root to be before the creation of the image.

Solution 3:

The general way which I use to display an image in tkinter is:

import Tkinter as tk
root = tk.Tk()
image1 = tk.PhotoImage(file = 'name of image.gif')
# If image is stored in the same place as the python code file,# otherwise you can have the directory of the image file.
label = tk.Label(image = image1)
label.image = image1 # yes can keep a reference - good!
label.pack()
root.mainloop()

In the above case it works but you have something like:

import Tkinter as tk
image = tk.PhotoImage(file = 'DreamPizzas.gif') #here this is before root = tk.Tk()
root = tk.Tk()
# If image is stored in the same place as the python code file,# otherwise you can have the directory of the image file.
label = tk.Label(image = image)
label.image = image
label.pack()
root.mainloop()

this gives me a runtime error: too early to create image.

but you have said that your error is image pyimage9 doesn't exist, this is strange because at the top you have set filename to 'AP_icon.gif', so you would think that you get a different error as I dont know where pyimage9 comes from. This makes me think that maybe you are getting the file name incorrect somewhere? You also need to move root = tk.Tk() to the top under imports.

Solution 4:

Restart the Kernel to get rid of the error "TclError: image "pyimage9" doesn't exist"

Solution 5:

Try the following code as I am able to rectify the same error:

window=Tk()
c=Canvas(window,height=2000,width=2000)
p=PhotoImage(file='flower1.gif',master = c)
c.create_image(500,500,image=p)