Big Array With Random Numbers With Python
I need to generate a big array (or list) with random numbers ( 10⁵ numbers) . I was trying like that: vet = random.sample(range(10),100000) But when I try to run : vet = random.
Solution 1:
What you want is
[random.random() for _ in xrange(100000)]
From the random module documentation:
random.sample(population, k) Return a k length list of unique elements chosen from the population sequence. Used for random sampling without replacement.
so when calling random.sample(range(10), 100000)
you're trying to extract 100000 unique elements in a sequence of length 10 which obviously can't work.
Note that
random.random()
returns a floating value between [0 ; 1)random.randrange([start], stop[, step])
returns a random element from the sequencerange([start], stop[, step])
random.randint(a, b)
returns an integer value in [a ; b]- when using
random.sample
, the equalitylen(population) >= k
must hold
Solution 2:
I think you're after something like this:
vet = [random.randint(1,10) for _ in range(100000)]
Solution 3:
You can you the numpy function and create an array with N space filled with a random number
import numpy as np
vector_size = 10000
one_dimensional_array = np.random.rand(vector_size)
two_dimensional_array = np.random.rand(vector_size, 2)
tree_dimensional_array = np.random.rand(vector_size, 3)
#and so on
You can create matrix of random numbers using the function below and arrays also.
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