Access Ip Camera With Opencv

November 21, 2023 Post a Comment

Can't access the video stream. Can any one please help me to get the video stream. I have searched in google for the solution and post another question in stack overflow but unfort

Solution 1:

You can use this code to get live video feeds in browser.

for accessing camera other than your laptop's webcam, you can use RTSP link like this

rtsp://admin:12345@192.168.1.1:554/h264/ch1/main/av_stream"

where

   username:admin
   password:12345
   your camera ip address and port
   ch1 is first camera on that DVR
replace cv2.VideoCamera(0) with this link like this for your camera and it will work

camera.py

import cv2

classVideoCamera(object):def__init__(self):
        # Using OpenCV to capture from device 0. If you have trouble capturing# from a webcam, comment the line below out and use a video file# instead.self.video = cv2.VideoCapture(0)
        # If you decide to use video.mp4, you must have this file in the folder# as the main.py.# self.video = cv2.VideoCapture('video.mp4')def__del__(self):
        self.video.release()

    defget_frame(self):
        success, image = self.video.read()
        # We are using Motion JPEG, but OpenCV defaults to capture raw images,# so we must encode it into JPEG in order to correctly display the# video stream.
        ret, jpeg = cv2.imencode('.jpg', image)
        return jpeg.tobytes()

main.py

from flask import Flask, render_template, Response
from camera import VideoCamera

app = Flask(__name__)

@app.route('/')defindex():
    return render_template('index.html')

defgen(camera):
    whileTrue:
        frame = camera.get_frame()
        yield (b'--frame\r\n'b'Content-Type: image/jpeg\r\n\r\n' + frame + b'\r\n\r\n')

@app.route('/video_feed')defvideo_feed():
    return Response(gen(VideoCamera()),
                    mimetype='multipart/x-mixed-replace; boundary=frame')

if __name__ == '__main__':
    app.run(host='0.0.0.0', debug=True)

then you can follow this blog to increase your FPS of video stream

Solution 2:

Use code below to access ipcam directly through opencv. Replace the url in VideoCapture with your particular camera rtsp url. The one given generally works for most cameras I've used.

import cv2

cap = cv2.VideoCapture("rtsp://[username]:[pass]@[ip address]/media/video1")

whileTrue:
    ret, image = cap.read()
    cv2.imshow("Test", image)
    if cv2.waitKey(1) & 0xFF == ord('q'):
        break
cv2.destroyAllWindows()

Solution 3:

You can use urllib to read frames from video stream.

Baca Juga

import cv2
import urllib
import numpy as np

stream = urllib.urlopen('http://192.168.100.128:5000/video_feed')
bytes = ''whileTrue:
    bytes += stream.read(1024)
    a = bytes.find(b'\xff\xd8')
    b = bytes.find(b'\xff\xd9')
    if a != -1and b != -1:
        jpg = bytes[a:b+2]
        bytes = bytes[b+2:]
        img = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.IMREAD_COLOR)
        cv2.imshow('Video', img)
        if cv2.waitKey(1) == 27:
            exit(0)

Check this out if you want to stream video from webcam of your pc. https://github.com/shehzi-khan/video-streaming

Solution 4:

Thank You. May be, now urlopen is not under utllib. It is under urllib.request.urlopen.I use this code:

import cv2
from urllib.request import urlopen
import numpy as np

stream = urlopen('http://192.168.4.133:80/video_feed')
bytes = ''whileTrue:
    bytes += stream.read(1024)
    a = bytes.find(b'\xff\xd8')
    b = bytes.find(b'\xff\xd9')
    if a != -1and b != -1:
        jpg = bytes[a:b+2]
        bytes = bytes[b+2:]
        img = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.IMREAD_COLOR)
        cv2.imshow('Video', img)
        if cv2.waitKey(1) == 27:
            exit(0)

Solution 5:

You can Use RTSP instead of direct video feed.

Every IP Camera have RTSP to Stream Live Video.

So you can use RTSP Link instead of videofeed

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