Remove Even Numbers From A List

How can I remove even numbers from a list? a = [] i = 0 while i < 10: c = int(raw_input('Enter an integer: ')) a.append(c) i += 1 # this is the same as i = i +

Solution 1:

Why not preventing the append if the number is even, instead of adding and then checking for removal?

a = []
counter = 0
while counter < 10:
    c = int(raw_input('Enter an integer: ')) 
    if c % 2 != 0:
        a.append(c)
    counter += 1print(a)

Solution 2:

i is reassigned by the for statement. Use a different variable.

Solution 3:

If you want to see how to 'filter' a list according to a predicate, here is an example:

a_without_even = filter(lambda x: x%2==1, a)

Solution 4:

def removalDiffMethod(self, array):
    l=0
    r=len(array)
    while l<r:
        ifarray[l]%2==0:
            array[l:r] = array[l+1:r+1]
            r-=1else:
            l+=1returnarray[:r]

Solution 5:

Something like this?

your_dirty_list = [2,3,3,3,4,4,2,2,7,7,8] 
your_clean_list = [clean_dude for clean_dude in your_dirty_list if clean_dude % 2]

Out[]: [3, 3, 3, 7, 7]