Python - Regex To Match Url With Mongo Object Id

I am trying to write a regex that matches a url of the following format: /api/v1/users//submissions Where an example of a mongo_object_id is 556b352f87d4693

Solution 1:

This will do (considering 24 hex chars), using raw keyword before string so no need to escape with double slashes:

r'\/api\/v1\/users\/([a-f\d]{24})\/submissions'

Python console:

>>> re.findall(r'\/api\/v1\/users\/([a-f\d]{24})\/submissions','/api/v1/users/556b352f87d4693546d31185/submissions')
['556b352f87d4693546d31185']

Solution 2:

It looks like an object's ID is a hexadecimal number, which means that it's matched by something as simple as this:

[0-9a-f]+

If you want to make sure it's always 24 characters:

[0-9a-f]{24}

Toss that between the slashes:

/api/v1/users/([0-9a-f]{24})/submissions

And it should work.

Note: You will probably have to escape the slashes, depending on how Python's regex syntax works. If I remember right, you can do this:

import re
re.findall(r'/api/v1/users/([0-9a-f]{24})/submissions', url)

or

re.findall(r'/api/v1/users/([0-9a-f]{24})/submissions', url, re.I)

if you wanna make the whole thing case-insensitive.