How To Find The Active Number Of Elements On A Single Column/row Using Openpyxl In Python?

I am using openpyxl. I have the below basic spreadsheet. I am trying to just get the active number of elements in a particular column using len() and filter but still not gett

Solution 1:

Spreadsheets are tables of rows and columns so if a spreadsheet has 30 rows then all columns have 30 cells. As to whether a cell is active or not, you have to decide what are the criteria for this but this is trivial to do:

not_empty = [c for c in ws.iter_rows(min_col=1, max_col=1, values_only=True) if c[0] is not None]
print(len(not_empty))

Solution 2:

Question: get the active number of elements in a particular column

---

Worksheet:

Title   Title   Title   
1       3       4   
None    None    None    
1       3       4   

min_col = 1  # 'A'
val_counter = 0

# Iterate all Rows, starting at 'min_row='
# Iterate only ONE Column, therefore 'min_col=' and 'max_col=' have the same value
# Returns a Tuple of Column Values ((value A2,), (value A3), ...)

for cells in ws.iter_rows(min_row=2, 
                          min_col=min_col, max_col=min_col,
                          values_only=True):
    value = cells[0]

    # Condition, which to count
    if value is not None:
        val_counter += 1

print('Values are {}'.format(val_counter))
# >>> Values are 2

---

OOP Solution:

Extending openpyxl class Worksheet with a .filter(... methode.

import openpyxl

class Worksheet:
    def __init__(self, pyxl):
        for attr in ['filter', 'filter_list']:
            setattr(pyxl.worksheet.worksheet.Worksheet, 
                    attr, 
                    getattr(Worksheet, attr)
                   )

    def filter(self, f, range=None, values_only=True):
        cells = self.iter_rows(min_row=range[0],
                               min_col=range[1],
                               max_row=range[2],
                               max_col=range[3],
                               values_only=values_only
                              )

        for row in cells: 
            yield from (c for c in row if f(c))

    def filter_list(self, f, range=None, values_only=True):
        return [v for v in self.filter(f, range, values_only)]

# Extend openpyxl Worksheet
Worksheet(openpyxl)

Usage:

wb = openpyxl.Workbook()
ws = wb.active

# Add some test data
ws.append(['Title', 'Title', 'Title'])
for r in range(3):
    if r == 1:
        ws.append([None, None, None])
    else:
        ws.append([1, 3, 4])


# Filter Values, where Cell.value is not None
# range(min_row, min_col, max_row, max_col)
# Return a List of Values
cells = ws.filter_list(lambda v: v is not None, 
                       range=(2, 1, ws.max_row, 1)

print('Values are {}'.format(len(cells)))
# >>> Values are 2