Why This Url Pattern Is Not Working?

from views import login from django.conf.urls.defaults import * urlpatterns = patterns('', *** (r'([a-zA-Z0-9]+)/login/$', login, name='login'), ) showing me the syntax error

Solution 1:

You need to use the url() function if you're using the name keyword:

url(r'([a-zA-Z0-9]+)/login/$', login, name='login'),

And the order of parameters to the {% url %} tag has the url name first. So it should be:

{% url login slug %}

Solution 2:

tuple literals don't have named arguments. Try url() instead.

    url(r'([a-zA-Z0-9]+)/login/$', login, name='login'),

Solution 3:

the way u are using the {% url slug login %} is not the correct syntax you have to write the name which you wrote in your urls for that template, i.e {% url login %} This is according to your url, try this it will work.........